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The resistances of 80 ohm and Voltmeter are in parallel combination,
Thus, 1 / R' = 1/80 + 1/80
1 / R' = 2/80 = 1/40
R' = 40 ohm.........●
Now, R' and 20 ohm resistances are in series combination,
Thus, Total resistance of the circuit,
R = R' + 20
R = 40 + 20
R = 60 ohm.........●
Now, Current in the circuit,
I = E/R
I = 2 / 60
I = 1 / 30 Ampere.
Now,
Reading of Voltmeter =>
V = I × R'
V = ( 1/30 ) × 40
V = 40 / 30 = 4 / 3
V = 1.33 Volts.......●
Thus, Option 'C' is correct.
●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
Thus, 1 / R' = 1/80 + 1/80
1 / R' = 2/80 = 1/40
R' = 40 ohm.........●
Now, R' and 20 ohm resistances are in series combination,
Thus, Total resistance of the circuit,
R = R' + 20
R = 40 + 20
R = 60 ohm.........●
Now, Current in the circuit,
I = E/R
I = 2 / 60
I = 1 / 30 Ampere.
Now,
Reading of Voltmeter =>
V = I × R'
V = ( 1/30 ) × 40
V = 40 / 30 = 4 / 3
V = 1.33 Volts.......●
Thus, Option 'C' is correct.
●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
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