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( 1 - x² ) d²y / dx² - x dy / dx = 4
Step-by-step explanation:
Given---> y = ( Sin⁻¹x )² + ( Cos⁻¹x )²
To find ---> ( 1 - x² ) d²y / dx² - x dy / dx = ?
Solution--->
(1) plzz see the attachment
(2) First we differentiate given equation with respect to x , using formulee as follows
(a) d / dx ( Sin⁻¹x ) = 1 / √( 1 - x² )
(b) d / dx ( Cos⁻¹x ) = - 1 / √( 1 - x² )
(3) In fourth step we multiplying whole equation by √(1-x²)
(4) In 6th step we again differentiate the equation we get in fifth step and applying product rule as follows
d/dx ( u v ) = u d/dx (v) + v d/dx (u)
(5) In 8th step we use two formulee
d/dx ( √x ) = 1 / 2√x and
d / dx ( x² ) = 2x
(6) In 11th step we multiply whole equation by √(1-x²)
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