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Given, E is the mid point of AD
AB//CD and EF // AB
To prove, F is the mid point of BC
Proof : since AB//CD and EF// AB
Therefore EF // CD
( lines which are parallel to the same line are parallel to one another )
So, E is the mid point of AB
And EF // CD
Therefore F is the mid point of BC [ by converse of mid point theorem]
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