Question

prove that: tan (90-B) = cot B

Answer 1

tan A = cot B ------------ ( eq. i)
{ given }
also, tan A = cot ( 90 - A ) ------------ ( eq.ii ) { complimentary angle }
From eq. i & ii -
cot B = cot ( 90°- A )
⇒ B = 90° - A.
⇒ 90 ° = A + B.
⇒ A + B = 90 °. [ PROVED ] .
4.7

Answer 2

$\mathcal\red{Heyya}$❤

$\bf\red{\underline{Solution:-}}$

It is given that

tan A = cot B

⇒tan A=tan (90° −B )        

{ °•° cot B = tan ( 90° − B ) }

⇒A = 90° −B

⇒A + B= 90°

Hence Proved

$\bf\red{Thank\:You}$☺