Math, asked by gopalbhati, 1 year ago

what must be subtracted from a³b+6a²b²-7ab+4 to get -7a²b²+2a³b+6ab-1

Answers

Answered by mysteryhat48
0

Answer:

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Step-by-step explanation:

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Answered by gamerayush52
0

Step-by-step explanation:

=(7a²b²+2a³b+6ab-1) + a³b+6²b²-7ab+4

= 7a²b²+2a³b+6ab-1 + a³b+6²b²-7ab+4

= 12a²b²+3a³b-ab-3 Ans

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