Question

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Answer 1

Answer:

the answer is explained below

Step-by-step explanation:

dimensions 24*28 and 16*20

this can easily be solved using the formula-.

Answer 2

$\huge \fbox \pink{Solution:}$

$\textbf{From The Figure it is clear that}$

$a + 16 + a = 24$

$⇒2a = 8$

$⇒a = 4 \: cm$

$\textbf{Similarly} \: b + 20 + b = 28$

$⇒2b = 8$

$⇒b = 4 \: cm$

Also it is given that width of each section is same,

$\text{i.e \: a = b = 4 \: cm}$

Each of the four sections of the frame form's trapezium

we Know that area of Trapezium

$= \frac{1}{2} \text{(sum \: of \: parallei \: sides )} \times height$

Then area of upper and lower section of Frame

$= \frac{1}{2} (16 + 24) \times 4$

$\text{[∴ \: parallel \: sides \: are \: 16 \: cm \: ] }$

$\text{[height \: = \: 4 \: cm]}$

$= \frac{1}{2} \times 40 \times 4 = 80 \: {cm}^{2}$

similarly area of left and right section of Frame

$= \frac{1}{2} (20 + 28) \times 4$

$\text{[∴ \: parallel \: sides \: are \: 20 \: and \: 28\: cm \: ] }$

$\text{[height \: = \: 4 \: cm]}$

$= \frac{1}{2} \times 48 \times 4 = 96 \: {cm}^{2}$

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