Chemistry, asked by purnima3061977, 8 months ago

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Answered by anu012
2

1. Al(OH)3+NaNO3 gives rise to AlNO3+Na(OH)3

2.Al+cucl2 gives rise to Alcl3+cu

3.cl(g) +Na gives rise to Nacl

4.AlSO4+ BaCl gives rise to Alcl+BaSO4

5.Fe+H2O gives rise to Mgo+H2

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Answered by ps968296
1

Answer:

 \blacksquare {\red{Al(OH)_3 + 3NaNO_3 \Rightarrow Al(NO_3) _3+ 3NaOH =>{\large {\mathfrak {\underline {Balanced}}}}}}

 \rule{300} {2}

 \blacksquare {\green {2Al + 3CuCl_2 \Rightarrow 2AlCl_3 + 3Cu=>{\large {\mathfrak {\underline {Balanced}}}}}}

 \rule{300} {2}

 \blacksquare{\pink {Cl + Na \Rightarrow NaCl=>{\large {\mathfrak {\underline{Balanced}}}}}}

 \rule{300} {2}

 \blacksquare{\blue {Al_2(SO_4)_3 + 3BaCl_2 \Rightarrow 2AlCl_3 +3BaSO_4=>{\large {\mathfrak {\underline{Balanced}}}}}}

 \rule{300} {2}

 \blacksquare Fe + H_2O \Rightarrow FeO. Fe_2O_3 + H_2

 \rule{300} {2}

Thank You.

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