Question

plz answer fast i will mark as brainliest​

Answer 1

Answer:

area of ∆ABD = 1/2 × B×H = 1/2×4×8 = 16cm^2

area of ∆ BDC =1/2 ×base ×height = 1/2×8×6= 24cm²

area of quadrilateral = area of ∆ABD + area of ∆BDC

=16+24 = 40 cm²

Please mark as brainliest.