Question

Plz answer fast,I will mark u as brainliest..

Answer 1

ANSWER

now .....p=20000N/cm^2=2×10^9 dyne/cm^2

bulk modulus (k)=0.80×10^10N/m^2

=0.80×10^10×10^5/10^4 dyne/cm^2

=0.80×10^11dyne /cm^2

now ...

$k = \frac{p}{ \frac{dv}{v} }$

putting the values......

$\frac{dv}{v} = \frac{2 \times 10 {}^{9} }{0.80 \times 10 {}^{11} } \\\frac{dv}{v} = 0.25 \\ dv = 0.25 \times v \\ \\ so \: new \: volume \\ (v - dv)= 0.75v \\ \\ \\mass \: \: of \: v \: volume =( 11.4 \times v) \: gm \\ \\ therefore \: density \\ d = \frac{11.4v}{0.75v} \\ d = 15.2 \: gm.cm {}^{ - 3}$

new density ISS=15.2 gm/cm^3

Answer 2

ANSWER:

may be this answer is correct