Question

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Answer 1

Answer:

Let age of son 6 years before be x

then mother's age = x 2

then, persent age son =x+6

mothers age =x 2+6

After 3 year,

son =x+6+3=x+9

mother =x 2 +6+3=x 2 +9

A.T.Q

x 2+9=3(x+9)

x 2 +9=3x+27

x 2−3x−18=0

x 2 −6x+3x−18=0

x(x−6)+3(x−6)=0

(x+3)(x−6)=0

x=6 (-3 will neglect)

Persent age of mother = x 2 +6⇒36+6=42

Son = x+6=6+6=12

Step-by-step explanation:

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