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given. = a quadrilateral. ABCD. AB=AD. AD is bisector
Toprove. = ABC=~ADC
BC=DC
proof= in ABC=ADC
AB=AD. (given)
AD=AD. (common)
AB=CD. (side of quad. )
by SSS rule
ABC=~ADC
vBC=DC. (by c. p. c. t. )
i hope this answere help you.
Please click thanku button
Toprove. = ABC=~ADC
BC=DC
proof= in ABC=ADC
AB=AD. (given)
AD=AD. (common)
AB=CD. (side of quad. )
by SSS rule
ABC=~ADC
vBC=DC. (by c. p. c. t. )
i hope this answere help you.
Please click thanku button
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