Question

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Answer 1

||✪✪ GIVEN ✪✪||

• Man is 4 times old as her daughter .
• After 16 years he will be twice as old as her daughter.
• Daughter age ?

|| ✰✰ ANSWER ✰✰ ||

Lets Assume That, Daughter Present age is = x years .

Than, Father present age will be = 4x .

Now,

→ After 16 years daughter will be = (x+16) years old.

→ After 16 years father will be = (4x + 16) years old.

So,

→ (4x+16) = 2(x+16)

→ 4x - 2x = 32 - 16

→ 2x = 16

Dividing both sides by 2,

→ x = 8 years.

Hence , Daughter Present age is 8 years old.

Answer 2

Answer:

4x=y

after 16 yrs

4x+16=2x

2x=-16

x=-16/2

x=8,y=32

x=24,y=48