Plz answer fast Q34
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Firstly R2 and R3 are in series so
R`=R1+ R2
=3+3
= 6ohm
Now the R` and R4 are in parallel so
R•=1/R`+R4
=1/6+1/3
=1+2/6
=3/6
=1/2
=2ohm
Now R• and R 1 and R1 are in series so
R°=R•+ R1+ R1
=2+3+3
=8ohms
The total equivalent resistance to the circuit is 8 ohm which will be shown in the ammeter
Hope this helps
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