Question

plz answer fast step by step​

Answer 1

Ths sum of arithmetric progression is
S=n2(a+l), where n is the number of terms, a is the first term and l is the last term.

The sum of integres 1 to 100 which is divisible by 2 is
S2=2+4+6+…100=502⋅(2+100)=2550
and, the sum of integers divisible by 5 is
S5=5+10+15+…100=202⋅(5+100)=1050

You may think the answer is S2+S5=2550+1050=3600 but this is wrong.

2+4+6+…100 and 5+10+15+…100 have common terms.
They are integers divisible by 10, and their sum is
S10=10+20+30+…100=102⋅(10+100)=550

Therefore, the answer for this question is S2+S5−S10=2550+1050−550=3050

Answer 2

my answer is more easy to understand , so mark it brainliest
answer is 3050