Plz answer fast the questions which I have tick marked
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sakthishamifb:
hey hi
i wanna ask you something
hi
hi
do you know anyone named kushi
khushi??
ok then if you dont know leave it
what is your name
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Answered by
1
hope this answer will help you.
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here is your answer.
a=1, d=1 and n=100 so,
Sn=n/2+[2a+(n-1)d]
s100=100/2+[2×1+(100-1)×1]
s100=50+[2+99]
s100=50+101
sorry its a wrong answer
now here is the right answer..
a=1,d=1,n=100 so, Sn=n/2[2a+(n-1)d], s100=100/2[2×1+(100-1)×1], s100=50(2+99), s100=50×101, s100=5050
so sum of first 100 natural numbers is 5050
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