PLZ ANSWER FAST ....WHAT IS THE POLAR FORM OF -1+i ?????????
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Answer:
-1 + i = √2 exp ( 3 π i / 4 )
= √2 cis ( 3 π / 4 )
Step-by-step explanation:
Let's put z = -1 + i.
Its norm is |z| = √( 1² + 1² ) = √2.
Plotting on a diagram, it is in the upper left quadrant, making a 135° with the positive x-axis. Remembering that π corresponds to half way around the circle (i.e. 180°), this is 135/180 = 3/4 of the way there, so the argument is 3π/4.
[ More formally, tan θ = 1 / -1 = -1, so θ is 3π/4 or -π/4. Since the real part Re(z) = -1 is negative, we conclude that θ = 3π/4. A diagram is easier. ]
So
z = √2 exp ( 3 π i / 4 )
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