plz answer for these two questions
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3136 is the correct answer
nomicccccccc:
I want the 2nd
plz.......... my dear
Sum of consecutive odd numbers is given by
Sn=1+3+5⋯+(2n−1)=∑(2n−1)=n2
3136=562⟹n=56
So 56 consecutive odd numbers starting from 1to(2n−1)=111 should be added to get 3136 as perfect square.
Sn=1+3+5⋯+(2n−1)=∑(2n−1)=n2
3136=562⟹n=56
So 56 consecutive odd numbers starting from 1to(2n−1)=111 should be added to get 3136 as perfect square.
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