plz answer for this....
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We know that the angle sum of a quadrilateral is 360..
Now, we know that
<A = <C
<B= 2<A
<D = <1/2 A
<A + <B + <C + <D = 360°
Substituting all the values..
<A + 2<A + <A + <1/2<A
4<A + 1/2<A = 360
9/2<A = 360
<A =360×2/9
<A = 80°
Now we've found the value of <A, We just have to substitute again..
<A = <C
∵<A = 80°
<C = 80°
<B = 2<A
<B = 2 × 80
=160°
<D = 1/2<A
= 1/2 × 80
= 40°
Therefore, <A = 80°, <B = 160°, <C = 80°, and <D = 40°
Hope it helps!!
Pls Make it brainliest.. and one day your answer will also be..
Now, we know that
<A = <C
<B= 2<A
<D = <1/2 A
<A + <B + <C + <D = 360°
Substituting all the values..
<A + 2<A + <A + <1/2<A
4<A + 1/2<A = 360
9/2<A = 360
<A =360×2/9
<A = 80°
Now we've found the value of <A, We just have to substitute again..
<A = <C
∵<A = 80°
<C = 80°
<B = 2<A
<B = 2 × 80
=160°
<D = 1/2<A
= 1/2 × 80
= 40°
Therefore, <A = 80°, <B = 160°, <C = 80°, and <D = 40°
Hope it helps!!
Pls Make it brainliest.. and one day your answer will also be..
ShAkEelBo55:
thank u sooooooo much
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