Math, asked by nenna123, 1 year ago

plz answer

i will mark brailiest!

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Answered by Varun1870
1
x³-2x²-x+2
x²(x-2) -1(x-2)
(x-2) (x²-1)
(x-2) (x+1) (x-1)

f(x) = x³+13x²+32x+20
f(-1) = (−1)³+13(−1)²+(32)(−1)+20
(−1)³+13(−1)²+(32)(−1)+20
=0

So,x+1 is the factor of f(x)
x³+13x²+32x+20/x+1
(x+1) (x²+12x+20)
(x+1) (x+2) (x+10)
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