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here multiply the 3rd equation by 2so that
2H2+O2-------2H2O so its change in enthalphy also doubles =-572kj/mol
reverse the equation 2H2O-------- 2H2+O2 so enthalphy =+572kj/mol
CO2--------C+O2 =+393kj/mol
by adding both equations we get CO2+2H2O------CH3-OH+3/2O2
2H2+O2-------2H2O so its change in enthalphy also doubles =-572kj/mol
reverse the equation 2H2O-------- 2H2+O2 so enthalphy =+572kj/mol
CO2--------C+O2 =+393kj/mol
by adding both equations we get CO2+2H2O------CH3-OH+3/2O2
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