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if a and b are 2 positive integers such that a+b=ab+ba.then find the value of a^2+b^2
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Two positive integers a and b are such that a + b =a/b + b/a. What is the value of a^2 + b^2?
S
a+b=a/b+b/aa+b=a/b+b/a
-> Now take L.C.M
a+b=(a2+b2)/aba+b=(a2+b2)/ab
-> Cross multiplying
(a+b)ab=a2+b2(a+b)ab=a2+b2
a2.b+b2.a=a2+b2a2.b+b2.a=a2+b2
Take a2a2 and b2b2 common
a2(b−1)+b2(a−1)=0a2(b−1)+b2(a−1)=0 --(1)
Now since aa and bb are positive integers - their square can’t be zero.
So in order to make the equation 1 equal to zero:
(b−1)(b−1) and (a−1)(a−1)both has to be 00.
Therefore,
b−1=0b−1=0 =>b=1b=1
and,
a−1=0a−1=0 =>a=1a=1
Hence a=b=1
dhonisuresh0703:
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