Question

Q= A cricket ball is thrown at a speed of 28 ms-¹ in a direction 30 above the horizontal calculate a) the maximum height b) time taken by the ball to return c) the distance from the thrower to the point where the ball return to the same level ?

Answer 1

a) 9.8
b) 2.8
c) 678.16

Answer 2

Answer:

Answer : a) 39.2 m

b) 2.8 sec.

c) 19.6 m

Explanation:

a) maximum height = u^2/2g = 28x28/2x10 = 39.2 m

b) time = 2(usin30/g) =2(28/2x10) = 2.8 sec.

c) Range = u^2sin^2 30"/g = 28x28/4x10 = 19.6 m.