Math, asked by suchitra01, 1 year ago

plz answer it correctly
plz don't give rubbish answers
plz solve it and give answer?!!!

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Answers

Answered by Anonymous
4
L.H.S
sec^4θ - sec^2θ
= sec^2 θ [ sec^2 θ - 1 ] { taking sec^2 θ as common }

= sec^2θ × tan^2θ

now R.H.S

tan^4θ + tan^2θ
= tan^2θ {tan^2θ +1}
=tan^2θ × sec^2θ
=or sec^2θ . tan^2θ

this means L.H.S= R.H.S

Palak1234: Thanks
suchitra01: why
Anonymous: welcome
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