Math, asked by KvKt2217, 1 year ago

plz... ANSWER it fassst....

I'll mark u brainliest​

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Answers

Answered by jyotirmaykrjha
2

Answer:

Please Find the Attached File.....

Plz. Mark As BRAINLIEST.....

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KvKt2217: thanks for the answer but I am not able to view the attachment......
Answered by srijansoham
5

Answer:

By pythagoras theorem, AB²=  AD² + BD² (ΔABD)

                                         AC² = AD² + DC² (ΔADC)

Adding both equations, we get

AB² + AC² = AD² + BD² + AD² + DC²

∵ BD = DC we can get:

AB² + AC² = AD² + BD² + AD² + BD²

                =   2(AD²) + 2(BD)²

=> AB² + AC² = 2(AD² + BD²) Hence proved

PLEASE MARK AS BRAINLIEST :)

                                           


srijansoham: Brainliest....plss
KvKt2217: Pythagoras applies for rt. angled ∆ but the given AD is not altitude.... it is median...
srijansoham: its only possible to prove if its right triangle
KvKt2217: the question is from the chapter straight lines class 11....
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