Math, asked by dasbeauti110, 5 months ago

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Answered by shaider
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Find the roots of the quadratic equation 6x2-x-2=0.

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 0

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 0

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 0

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 02x = -1

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 02x = -1x=

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 02x = -1x=Hence x =

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 02x = -1x=Hence x =and x =are the roots of the equation

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 02x = -1x=Hence x =and x =are the roots of the equation3x - 2 = 0

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 02x = -1x=Hence x =and x =are the roots of the equation3x - 2 = 03x = 2

Find the roots of the quadratic equation 6x2-x-2=0.6x2 – x- 2 = 0We factorize by splitting the middle term method6x2 - 4x + 3x - 2 = 02x (3x - 2) + 1 (3x- 2) = 0 (2x + 1) (3x - 2) = 02x + 1 = 02x = -1x=Hence x =and x =are the roots of the equation3x - 2 = 03x = 2X =2/3

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