Question

plz answer it tomorrow is my exam

Answer 1

Answer- Q. Factorise (x+9)³

Solution- As we know, (a+b)³= a³+b³+3a²b+3ab²

Here, let a= x, b=9

Substituting values,

(x+9)³= x³+(9)³+3×(x)²×9+3×x×(9)²

        = x³+ 729 + 27x² + 243x

Q. Factorise (x+2)²

Solution- As we know, (a+b)²= a²+2ab+b²

Let a= x, b= 2

Substituting values,

(x+2)²= x²+ 2×x×2 + (2)²

        = x²+4x+4

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