Question

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Answer 1

Answer:

I think this is helpful to you 50km/h

Explanation:

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Answer 2

Explanation:

As given in the question speed of the car when going to college = 20Km/h,

And speed of the car while returning back to home = 30Km/h.

Let the distance from Akhil’s home to college be x Km, so total distance travelled by Akhil is 2x Km.

Formula of speed Speed = DT(where D is the distance travelled and T is the time taken)

Let the time taken by Akhil while going to college be t1

Substituting the value in formula

20Kmh=xKmt1

Getting the value of t1

t1=x20h

Similarly, assuming the time taken by Akhil while coming back to home be t2

Substituting the value in formula

30Kmh=xKmt2

Getting the value of t2

t2=x30h

Total time taken in complete trip = t1+t2

i.e. TT = (x20+x30)h

Taking LCM

TT = x12h

As discussed above total distance i.e. (TD) = 2xKm/h.

As we know that average speed = TDTT (where TT is the total time and TD is the total distance travelled)

Substituting values

Average speed = 2xx/12(total distance is 2x whereas total time is x/12)

So average speed = 2×12=24Km/h

So the final answer is 24Km/h.