Question

plz answer me fast......

Answer 1

in rt ABD,AB²=AD²+BD²
IN RT. ACD,AC²=AD²+CD²
subtract AB²-AC²=AD²+BD²-AD²-CD²
AB²-AC²=BD²-CD²=(3CD)²-CD²
AB²-AC²=8CD²
BC=BD+CD=3CD+CD=4CD
CD=BC/4
NOW,AB²-AC²=8(BC/4)²
AB²-AC²=8BC²/16
AB²-AC²=BC²/2
2AB²-2AC²=BC²
2AB²=2AC²+BC²