Physics, asked by rajshrigupta12321, 1 month ago

plz answer me
physics ch. pressure in fluids numericals​

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Answered by lathaguru434
0

Answer:

flueids numericals bro this is your answer

Answered by Anonymous
1

From question, we have;

  • Total pressure = 2 pa
  • Atmospheric pressure = 10⁵ pa

Now, we know that,

\small\boxed{\sf{Pressure \:in \:water\: = \:Atmospheric\: pressure\: + \:water \:pressure}}

It can be written as,

= Total pressure = Pa + hdg

= 2 =10⁵+ ( 10³ × 9.8 )

= 2 = 1 + h ( 10³ × 9.8 )

  • {because 10⁵ Nm⁻² = 1 atmosphere}

= 2 - 1= h × 9.8 × 10³

= 1 = h × 9.8 × 10³

= 1/9.8 × 10³ = h

= 10⁵ × 10/98 × 10³ = h

  • { again 10⁵ Nm⁻² = 1 atmosphere }

= 10⁶ × 10⁻³/98 = h

= 10⁶⁻³/98 = h

= 10³/98 = h

= 1000/98 = h

= 10.2 m = h

Therefore, the depth is 10.2 metre.

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Thank youu!! :))

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