Question

plz answer me the question plz... I can't do this sum... plz plz plz....​

Answer 1

Answer:

it's better to use digest

Answer 2

Answer:

1/a+1/b+1/c=0

Step-by-step explanation:

Let take P^a=Q^b=R^c=K

Add log for both sides,

LogP^a=LogQ^b=LogR^c=LogK

So alogP=blogQ=clogR= logK

a=logP/logk

b=logQ/logk

c=logR/logK

thus 1/a+1/b+1/c= logp+logq+logr/logK

After that =log(pqr)/logk

Already mentioned pqr=1

so =log(1)/logk     i.e log1=0

    =  0/logk

Hence proved 1/a+1/b+1/c=0