plz answer my hindi questions
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Number of 3 digit number div by 9 = ((999-108)/2)+1=100. Even 3 digit number div by 9 = 100/2 = 50. For n and n^2 to leave the same remainder, the even number must end with 0 or 6. Multiples of 9 - 18,36,54,72,90.
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