Question

plz answer my question.....​

Answer 1

EXPLANATION.

Nth term of an Ap = 3 + 4n

To find common difference.

=> Nth term = 3 + 4n

=> put n = 1

=> 3 + 4 = 7

=> put n = 2

=> 3 + 4(2) = 11

=> put n = 3

=> 3 + 4(3) = 15

=> put n = 4

=> 3 + 4(4) = 19

Therefore,

Sequence = 7,11,15,19 .........

=> First term = a = 7

=> common difference = d = b - a

=> 11 - 7 = 4

Some related formula.

$\rm \to \: nth \: term \: of \: an \: ap \\ \rm \to \boxed{\: an = a \: + \: (n - 1)d}$

$\rm \to \: sum \: of \: nth \: term \: of \: an \: ap \\ \rm \to \boxed{ \: s_{n} = \frac{n}{2} (2a \: + \: (n - 1)d)}$

Answer 2

Answer:

⭐ Solution ⭐

✏Nth term of an Ap = 3 + 4n

➡To find common difference:-

=> Nth term = 3 + 4n

✳ put n = 1

=> 3 + 4 = 7

✳ put n = 2

=> 3 + 4(2) = 11

✳ put n = 3

=> 3 + 4(3) = 15

✳ put n = 4

=> 3 + 4(4) = 19

▶Therefore,

Sequence = 7,11,15,19 .............

✍ First term = a = 7

✍ common difference=d = b - a

=> 11 - 7 = 4

Hence, the correct option is c) 4

Step-by-step explanation:

HOPE IT HELP YOU