Question

plz answer my question.​

Answer 1

Answer:

2n+2n+2+2n+4=6(n+1)

6n+6=6n+6

(6n+6)/6=(6n+6)/6

n+1=n+1

Step-by-step explanation:

Answer 2

Answer :-

We have to prove that the sum of three consecutive even number is always divisible by 6 .

We have to prove that the sum of three consecutive even number is always divisible by 6 . According to the Euclid's Algorithm in order to be the number divisible by 6 it should be in the form of 6m .

Let the integer be a

Then as every even integer is in the form of 2a

Let the three consecutive even integer be

2a , 2a + 2 and 2a + 4

Now by the taking the sum of all

= 2a + (2a + 2) + (2a + 4)

= 6a + 6

Now taking 6 as common

= 6(a + 1)

As 6(a + 1) is equivalent to 6m

Hence Proved that sum of three consecutive even integer is always divisible by 6