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Answered by
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Answer:
Here's an easy prove-procedure:
Given that,
AB=BC=CD=DE
To prove:
AD=BE
Prove:
i. In quadrilateral ABCD,
AB=CD
& likewise, in quadrilateral BCDE,
BC=DE
So, both ABCD & BCDF are trapezium.
ii. In trapezium ABCD & BCDF,
AB:BC=CD:DE= BC:CD
=> AB/BC=CD/DE=BC/CD
So, both the trapeziums are congruent to each other.
iii. ABCD ≅ BCDF
Hence, AD=BE [Proved]
Answered by
1
Step-by-step explanation:
bro
thanks for your concern
but i don't need help
coz if you would have checKed my answers you wouldn't say this 450+maths answers in 666 answers
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