Question

Plz answer my question .... help me guys

the answer of above question 95 is. '0'
the answer of question 96 is '0'​

Answer 1

Answer:

yes answers of 95 and 96 are 0

Step-by-step explanation:

we use formula a^3+b^3=(a+b)^3-3x^2y-3xy^2

and a^3-b^3=(a-b)^3-3ab^2+3a^2b

and '^' simble is used for sensing to the power i mean a to the power 3, b to the power 3

agar kahi pe vi samajhne mai koi problem ho to just ask me...

95. given,x+y=4

now, x^3+y^3+12xy-64

=((x+y)^3)-3(x^2)y-3x(y^2)+12xy-64

=((x+y)^3)-3xy(x+y-4)-64

=((x+y)^3)-3xy(0)-64 bcs,x+y=4, given

=((4)^3)-64

=0

96.given,a=2b+6

or,a-2b-6=0

a^3-8b^3-36ab-216

=((a-2b)^3)+6(a^2)b-12a(b^2)-36ab-216

=((a-2b)^3)+6ab(a-2b-6)-216

=((a-2b)^3)+6(0)-216 bcs,given a-2b-6=0

=((6)^3)-216

=216-216 ,given ,a-2b=6

=0