plz answer my question, Q-11....
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very nice question
thank you
LCM(a,b) = 1000 = 2^3 *5^3
That means either a consist 3 twos or b contain 3 twos
Or one of a and b consist 3 twos and other one consist less than or equal to 3 twos
Twos
a 0|1|2|3 | 3
b 3|3|3|0,1,2|3
Total cases are 7
Same as with fives
LCM(b,c) = 2000= 2^4*5^3
Since two in b are less than or equal to 3 thus two in c must be 4
But for 5 again same
LCM(c,a) = 2000= 2^4*5^3
This case same as second case
Out of a,b,c two of them must consist 3 fives and the left one can consist any number of five from 0 to 2 and other one can also consist three fives
. . . Fives . . .
a |3 . |3 . |0,1,2|3|
b |3 . |0,1,2| 3 |3|
c|0,1,2|3 . | 3 |3|
Total no. Of cases = 10
Thus ordered no. Of pairs = 7*10 = 70
thank you
LCM(a,b) = 1000 = 2^3 *5^3
That means either a consist 3 twos or b contain 3 twos
Or one of a and b consist 3 twos and other one consist less than or equal to 3 twos
Twos
a 0|1|2|3 | 3
b 3|3|3|0,1,2|3
Total cases are 7
Same as with fives
LCM(b,c) = 2000= 2^4*5^3
Since two in b are less than or equal to 3 thus two in c must be 4
But for 5 again same
LCM(c,a) = 2000= 2^4*5^3
This case same as second case
Out of a,b,c two of them must consist 3 fives and the left one can consist any number of five from 0 to 2 and other one can also consist three fives
. . . Fives . . .
a |3 . |3 . |0,1,2|3|
b |3 . |0,1,2| 3 |3|
c|0,1,2|3 . | 3 |3|
Total no. Of cases = 10
Thus ordered no. Of pairs = 7*10 = 70
mili1978piku2:
thank you
.......but u were late
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