Question

plz answer only if you know ​

Answer 1

Step-by-step explanation:

t² - 3√5/2t - 5 = 0

» 2t² - 3√5t - 10/2 = 0

» 2t² - 3√5t - 10 = 0

Using Quadratic formula -

• -b ± √b² - 4ac/2a

here,

a = 2

b = -3√5

c = -10

Now,

» -(-3√5) ± √(-3√5)² - 4×2×-10/2(2)

» 3√5 ± √45+80/4

» 3√5 ± √125/4

» 3√5 ± 5√5/4

Zeroes are -

t = 3√5 + 5√5/4

» 8√5/4

» 2√5

and

t = 3√5 - 5√5/4

» -2√5/4

» -√5/2

Hence,

The zeroes are 2√5 and -5/√2

Formula Used -

Quadratic formula -

• -b ± √b² - 4ac/2a

Answer 2

$\huge \mathfrak{Answer:-}$

$\large\underline\mathrm{The \: zeroes \: are \: 2√5 \: and \: -√5/2.}$

$\large\underline\mathrm{Given:-}$

• α and β are zeroes of polynomial is t² - 3√5/2t - 5 = 0

$\large\underline\mathrm{To \: find}$

• Value of αβ.

$\implies$ t² - 3√5/2t - 5 = 0

$\implies$ 2t² - 3√5t - 10/2 = 0

$\implies$ 2t² - 3√5t - 10 = 0

$\large\underline\mathrm{Using \: formula:-}$

• -b +,- √b² - 4ac/2a
• a = 2
• b = -3√5
• c = -10

$\large\underline\mathrm{Solution}$

$\implies$ -(-3√5) +,- √(3√5)² - 4 × 2 × -10/2(2)

$\implies$ 3√5 +,- √45 + 80/4

$\implies$ 3√5 +,- √125/4

$\implies$ 3√5 +,- 5√5/4

$\implies$ t = 3√5 + 5√5/4

$\implies$ t = 8√5/4

$\implies$ t = 2√5

$\large\underline\mathrm{and}$

$\implies$ t = 3√5 - 5√5/4

$\implies$ t = -2√5/4

$\implies$ t = -√5/2

$\large\underline\mathrm{hence,}$

$\large\underline\mathrm{The \: zeroes \: are \: 2√5 \: and \: -√5/2.}$

$\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}$