Question

plz answer ..................qs no. 5

Answer 1

By rationalizing
$\sqrt{3} - \sqrt{2} = \frac{1}{ \sqrt{3} + \sqrt{2} }$
now,
${ (\sqrt{3} + \sqrt{2} )}^{x} + { (\sqrt{3} + \sqrt{2} )}^{ - x} = 10$
let this eq. below be 1st eq.
${ (\sqrt{3} + \sqrt{2}) }^{x} = t$
t+ 1/t = 10
${t}^{2} - 10t + 1 = 0$
by quadratic formula u will get the value of the and then put t in 1st eq and u will get the value

Answer 2

hope this helps you .