Question

plz answer question no.9​

Answer 1

Answer:

Explanation:

pls find the attachment

Answer 2

Explanation:

Let a resistor having resistance r

Then equivalent resistance in series

= 3r

Power = 10 W =

$\frac{ {v}^{2} }{3r}$

Therefore,

${v}^{2} = 30r$

Now, equivalent resistance in parallel

r/3

Then Power dissipation,

$= \frac{ {v}^{2} }{ \frac{r}{3} } = \frac{3 \times 30r}{r} = 90$

=90W