plz answer question number 9
plz answer soon don't give spam answer
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factors of 12 are 1 2 3 4 6 12
using x-2=0
x=2
p(2)=6×8-25×4+32×2-12
=48-100+64-12
=-112+112
=0
thus, x-2 is a factor of p(x).
Now divide p(x) by x-2
we will get
6x^2-13x+6
now we have to do middle term splitting of this equation
we will get (3x-2)(2x-3) as a result
Therefore (x-2) (3x-2)(2x-3) are the factors of p(x).
using x-2=0
x=2
p(2)=6×8-25×4+32×2-12
=48-100+64-12
=-112+112
=0
thus, x-2 is a factor of p(x).
Now divide p(x) by x-2
we will get
6x^2-13x+6
now we have to do middle term splitting of this equation
we will get (3x-2)(2x-3) as a result
Therefore (x-2) (3x-2)(2x-3) are the factors of p(x).
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proton1:
thanks a lot
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1
hope it will help you
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