Plz answer question with explanation
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Answered by
1
Let
No. of ₹1 coins = x
Value of ₹1 coins = 1*x = x
No. of ₹2 coins = y
Value of ₹2 coins = 2*y = 2y
ATQ
x/y = 5/4
x + 2y = 65
To find y put x= 5y/4 in the above equation
i.e
5y/4 + 2y = 65
(5y +8y)4 = 65
13y = 65*4
y = 65*4/13 = 5*4 = 20
Therefore option C is correct
No. of ₹1 coins = x
Value of ₹1 coins = 1*x = x
No. of ₹2 coins = y
Value of ₹2 coins = 2*y = 2y
ATQ
x/y = 5/4
x + 2y = 65
To find y put x= 5y/4 in the above equation
i.e
5y/4 + 2y = 65
(5y +8y)4 = 65
13y = 65*4
y = 65*4/13 = 5*4 = 20
Therefore option C is correct
Answered by
0
Let the number of ₹1 coin = 5x
So, the number of ₹2 coin = 4x
Amount from,
₹1 = ₹(1 × 5x) = ₹5x
₹2 = ₹(2 × 4x) = ₹8x
According to Question,
Total Amount = ₹65
5x + 8x = 65
⇒ 13x = 65
⇒ x = 65 / 13
⇒ x = 5
Number of Coins »
₹1 = 5x = 5(5) = 25
₹2 = 4x = 4(5) = 20
Hence, Option (C) is correct.
There are 25 coins of ₹1 and 20 coins of ₹2
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