plz answer the following question Q8
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2x²+px-15=0 then x=-5 is one of it's root
then, substitute x= -5 in equation
2(-5)²+p(-5)-15=0
(2×25)-5p-15 =0
50-15 = 5p
35=5p
p=7
then, substitute x= -5 in equation
2(-5)²+p(-5)-15=0
(2×25)-5p-15 =0
50-15 = 5p
35=5p
p=7
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