Question

plz answer the question.​

Answer 1

(sin + cos)( cot + tan )

( sin + cos) ( cos / sin + sin / cos)

( sin + cos ) ( cos^2 + sin^2/ cos*sin)

(sin + cos ) ( 1/ sin cos)

now ( sin + cos)

----------------

sin* cos

giving denominator to both

sin + cos

------ ------

sin*cos sin*cos

1 + 1

----- ---------

cos. sin

= sec + cosec

as all are in plus

= cosec + sec

Step-by-step explanation:

imp things

lcm

sin^2 + cos ^2 = 1

giving denominator

Answer 2

$\huge \pink {Hello\: Mate}$

Answer:

$\Large{L.H.S}$

$=>(Sinθ-Cosθ) (Cotθ+Tanθ)$

$=> (Sinθ-Cosθ) (\frac{Cosθ}{Sinθ} +\frac{Sinθ}{Cosθ})$

$=>(Sinθ-Cosθ) (\frac{ {Cosθ}^{2}+ {Sinθ}^{2}} {SinθCosθ})$

$=>(Sinθ-Cosθ) (\frac{1} {SinθCosθ})$

$=>\frac{Sinθ-Cosθ}{SinθCosθ}$

$=>\frac{Sinθ-Cosθ}{SinθCosθ}$

$=>\frac{Sinθ}{SinθCosθ} - \frac{Cosθ}{SinθCosθ}$

$=>\frac{1}{Cosθ} - \frac{1} {Sinθ}$

$=>\frac{1}{Cosθ} - \frac{1} {Sinθ}$

$=>Secθ - Cosecθ$

$\Large {R.H.S}$

$=> Secθ - Cosecθ$

$Hence\: L.H.S=R.H.S$

Hope it helps úh

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