Question

plz answer the question

Answer 1

In triangle PSQ,
${(pq)}^{2} = {(ps)}^{2} + {(sq)}^{2}$
${(pq)}^{2} = {12}^{2} + {16}^{2} = 144 + 256$
$= > {(pq)}^{2} = 400 = > 20 \: cm \:$
So by using Heron's formula calculating area of triangle PQR, a=PQ=20cm,b=RQ=48cm and c=PR=52 cm. s=(a+b+c)/2 =20+48+52/2=60 cm.
Area of triangle PQR=√s(s-a)(s-b)(s-c) =
√60(60-20)(60-48)(60-52) =√60(40)(12)(8) =√2400×96 =480 square centimetre . Area of triangle PSQ=1/2(base)(height) =1/2(12)(16)=96 square centimetre . Shaded area =480-96=384 square centimetre.

Answer 2

H = 20cm
a = 20cm b = 52cm and c = 48cm
S = 120/2 = 60cm
Area by herons formula = 480cm^2
Area of right triangle = 1/2*16*12= 96cm^2
Area of shaded region
480-96 = 384cm^2