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Anonymous:
'Fraid x = 2 is not correct. Try substituting it in the original equation to check!
Putting x = 2 into the original equation, the LHS is 1/0 + 1/0. This is definitely not equal to 2/3 !!
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x = 0 or x = 4
Hope this helps.
Step-by-step explanation:
1 / (x-1)(x-2) + 1 / (x-2)(x-3) = 2/3
=> [ multiplying everything by 3(x-1)(x-2)(x-3) ]
3(x-3) + 3(x-1) = 2(x-1)(x-2)(x-3)
=> 3x - 9 + 3x - 3 = 2x³ - 12x² + 22x - 12
=> 2x³ - 12x² + 16x = 0
=> x³ - 6x² + 8x = 0
=> x(x-2)(x-4) = 0
=> x = 0, 2 or 4
But x = 2 cannot be a solution to the original equation since that would result in division by 0, so that just leaves the solutions:
x = 0 and x = 4
Hello. Hope this helps you. Plz mark this brainliest. Have a great day!
THANKS BRO
You're welcome. Glad to have helped.
Mark this brainliest?
Ok
Ty
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