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Ans:- (a) When we connect two resistors in series and one resistor in parallel connection each of having resistance of 6ohm to get equivalent resistance be:-
Req=R1+R2[for series connections]
Req=(6+6)ohm=12ohm
Now,for parallel connection we have:-
1/Req=1/R1+1/R2
1/6+(Req of parrellel connection)
1/6+1/12=3/12=1/4
therefore,Req=4
- so,we find the required equivalent resistance for this circuit.
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