Question

plz answer the question correctly​

Answer 1

dividing as given

1/y + 1/x = 2 -----(1)

1/y - 1/x = 6

let assum 1/x = a & 1/y = b

a + b = 2

-a + b = 6

adding both

2b = 8

b = 4

so a = -2

as we assume 1/x = a & 1/y = b

so

x = -1/2 and y = 1/4

Answer 2

Answer:

$\dfrac{1}{4}$

Step-by-step explanation:

Given:

$\frac{x + y}{xy} = 2 \\ \\ \frac{x - y}{xy} = 6$

To find:

Value of y

Solution:

$\frac{x + y}{xy} = 2 \\ \\ \frac{x}{xy} + \frac{y}{xy} = 2 \\ \\ \frac{1}{x} + \frac{1}{y} = 2 \: \: \: \: \:....... (i)$

$\frac{x - y}{xy} = 6 \\ \\ \frac{x}{xy} - \frac{y}{xy} = 6 \\ \\ \frac{1}{y} - \frac{1}{x} = 6 \: \: \: \: ........(ii)$

Adding (i) and (ii) , I get ....

$\frac{1}{x} + \frac{1}{y} + \frac{1}{y} - \frac{1}{x} = 6 + 2 \\ \\ \cancel{ \frac{1}{x} } + \frac{1 + 1}{y} - \cancel\frac{ 1}{x} = 8 \\ \\ \frac{2}{y} = 8 \\ \\ \frac{1}{y} = 4 \\ \\ y = \frac{1}{4}$

Hence the required value of y is 1/4 .