Question

plz answer the question correctly​

Answer 1

${\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}$

50°

$<marquee>Explanation</marquee>$

☆ Let <ABT be x.

${\large{\blue{\bold{\underline{Given:-}}}}}$

▪︎ TB and TA are two tangents to a circle with center O.

${\large{\blue{\bold{\underline{SO,}}}}}$

=》 <TBO = <TAO = 90°.

☆ Also,

=》 <TBO+<TAO+<ATB+AOB = 360°.

{Angle sum property of quadrilateral}

=》 90°+90°+80°+<AOB = 360°.

=》 <AOB = 360°-260°

=》 <AOB = 100°

☆ And,

=》 <ABO = <BAO.

{Angle opposite to same radii i.e. same sides}

☆ Again,

=》 <ABO+<BAO+<AOB = 180°.

{Angle sum property of triangle}

=》 2<ABO+100° = 180°.

=》 2<ABO = 80°.

=》<ABO = 40°.

☆ Therefore,

=》<ABT = <TBO-<ABO

=》 <ABT = 90°-40°.

=》 <ABT = 50°

☆ Therefore angle ABT = 50°.

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$<marquee>✌✌THANKS✌✌</marquee>$