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p(x)=2x⁴+7x³–19x²–14x+30
its two zeroes are:
x=√2 and, x=–√2
(x–√2=0) and, (x+√2=0) are two factors.
similarly, (x–√2)(x+√2) =>g(x)=x²–2
is also a factor
Dividing p(x) by g(x);
q(x)=2x²+7x–15=0 (as its root is 'x' too)
=>2x²+10x–3x–15=0
=>2x(x+5)–3(x+5)=0
=>(2x–3)(x+5)=0
either, 2x-3=0 or x+5=0
=>x=3/2 or x=–5
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