Question

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Answer 1

By inspection we find that
$F(1)=0 \\hence \: (y-1)\: is\: the \:factor \:of\: F(y)\\ by \:using\: factor \:theorem\: 2 {y}^{2} (y - 1) \\+ 3y( y - 1) + (y - 1) \\= (y - 1)(2 {y}^{2} + 3y + 1) \\=(y - 1)(2 {y}^{2} + 2y + y + 1) \\= (y - 1)(2y + 1)(y + 1)$

Answer 2

Answer:

first we put y=1 so the whole will be zero then we find that y-1 is a factor tabhi y-1 se isko divide karenge phir aayega 2y^2+3y +1 fir isko splitting middle term se solve kr lenge aa jayega y=-1/2 or y=-1

Hope this will help you :)